(3x+1)^2+(x+2)^2=65

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Solution for (3x+1)^2+(x+2)^2=65 equation: 



(3x+1)^2+(x+2)^2=65

We move all terms to the left:

(3x+1)^2+(x+2)^2-(65)=0

We move all terms containing x to the left, all other terms to the right

(3x+1)^2+(x+2)^2=65

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